Integrand size = 16, antiderivative size = 346 \[ \int \frac {x^2}{(a+b \text {arcsinh}(c x))^{7/2}} \, dx=-\frac {2 x^2 \sqrt {1+c^2 x^2}}{5 b c (a+b \text {arcsinh}(c x))^{5/2}}-\frac {8 x}{15 b^2 c^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {4 x^3}{5 b^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {16 \sqrt {1+c^2 x^2}}{15 b^3 c^3 \sqrt {a+b \text {arcsinh}(c x)}}-\frac {24 x^2 \sqrt {1+c^2 x^2}}{5 b^3 c \sqrt {a+b \text {arcsinh}(c x)}}+\frac {e^{a/b} \sqrt {\pi } \text {erf}\left (\frac {\sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c^3}-\frac {3 e^{\frac {3 a}{b}} \sqrt {3 \pi } \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{5 b^{7/2} c^3}-\frac {e^{-\frac {a}{b}} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c^3}+\frac {3 e^{-\frac {3 a}{b}} \sqrt {3 \pi } \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{5 b^{7/2} c^3} \]
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Time = 0.66 (sec) , antiderivative size = 346, normalized size of antiderivative = 1.00, number of steps used = 22, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.562, Rules used = {5779, 5818, 5778, 3389, 2211, 2236, 2235, 5773, 5819} \[ \int \frac {x^2}{(a+b \text {arcsinh}(c x))^{7/2}} \, dx=\frac {\sqrt {\pi } e^{a/b} \text {erf}\left (\frac {\sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c^3}-\frac {3 \sqrt {3 \pi } e^{\frac {3 a}{b}} \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{5 b^{7/2} c^3}-\frac {\sqrt {\pi } e^{-\frac {a}{b}} \text {erfi}\left (\frac {\sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c^3}+\frac {3 \sqrt {3 \pi } e^{-\frac {3 a}{b}} \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{5 b^{7/2} c^3}-\frac {24 x^2 \sqrt {c^2 x^2+1}}{5 b^3 c \sqrt {a+b \text {arcsinh}(c x)}}-\frac {16 \sqrt {c^2 x^2+1}}{15 b^3 c^3 \sqrt {a+b \text {arcsinh}(c x)}}-\frac {8 x}{15 b^2 c^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {4 x^3}{5 b^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {2 x^2 \sqrt {c^2 x^2+1}}{5 b c (a+b \text {arcsinh}(c x))^{5/2}} \]
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Rule 2211
Rule 2235
Rule 2236
Rule 3389
Rule 5773
Rule 5778
Rule 5779
Rule 5818
Rule 5819
Rubi steps \begin{align*} \text {integral}& = -\frac {2 x^2 \sqrt {1+c^2 x^2}}{5 b c (a+b \text {arcsinh}(c x))^{5/2}}+\frac {4 \int \frac {x}{\sqrt {1+c^2 x^2} (a+b \text {arcsinh}(c x))^{5/2}} \, dx}{5 b c}+\frac {(6 c) \int \frac {x^3}{\sqrt {1+c^2 x^2} (a+b \text {arcsinh}(c x))^{5/2}} \, dx}{5 b} \\ & = -\frac {2 x^2 \sqrt {1+c^2 x^2}}{5 b c (a+b \text {arcsinh}(c x))^{5/2}}-\frac {8 x}{15 b^2 c^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {4 x^3}{5 b^2 (a+b \text {arcsinh}(c x))^{3/2}}+\frac {12 \int \frac {x^2}{(a+b \text {arcsinh}(c x))^{3/2}} \, dx}{5 b^2}+\frac {8 \int \frac {1}{(a+b \text {arcsinh}(c x))^{3/2}} \, dx}{15 b^2 c^2} \\ & = -\frac {2 x^2 \sqrt {1+c^2 x^2}}{5 b c (a+b \text {arcsinh}(c x))^{5/2}}-\frac {8 x}{15 b^2 c^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {4 x^3}{5 b^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {16 \sqrt {1+c^2 x^2}}{15 b^3 c^3 \sqrt {a+b \text {arcsinh}(c x)}}-\frac {24 x^2 \sqrt {1+c^2 x^2}}{5 b^3 c \sqrt {a+b \text {arcsinh}(c x)}}+\frac {24 \text {Subst}\left (\int \left (-\frac {3 \sinh \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{4 \sqrt {x}}+\frac {\sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{4 \sqrt {x}}\right ) \, dx,x,a+b \text {arcsinh}(c x)\right )}{5 b^4 c^3}+\frac {16 \int \frac {x}{\sqrt {1+c^2 x^2} \sqrt {a+b \text {arcsinh}(c x)}} \, dx}{15 b^3 c} \\ & = -\frac {2 x^2 \sqrt {1+c^2 x^2}}{5 b c (a+b \text {arcsinh}(c x))^{5/2}}-\frac {8 x}{15 b^2 c^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {4 x^3}{5 b^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {16 \sqrt {1+c^2 x^2}}{15 b^3 c^3 \sqrt {a+b \text {arcsinh}(c x)}}-\frac {24 x^2 \sqrt {1+c^2 x^2}}{5 b^3 c \sqrt {a+b \text {arcsinh}(c x)}}-\frac {16 \text {Subst}\left (\int \frac {\sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c x)\right )}{15 b^4 c^3}+\frac {6 \text {Subst}\left (\int \frac {\sinh \left (\frac {a}{b}-\frac {x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c x)\right )}{5 b^4 c^3}-\frac {18 \text {Subst}\left (\int \frac {\sinh \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c x)\right )}{5 b^4 c^3} \\ & = -\frac {2 x^2 \sqrt {1+c^2 x^2}}{5 b c (a+b \text {arcsinh}(c x))^{5/2}}-\frac {8 x}{15 b^2 c^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {4 x^3}{5 b^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {16 \sqrt {1+c^2 x^2}}{15 b^3 c^3 \sqrt {a+b \text {arcsinh}(c x)}}-\frac {24 x^2 \sqrt {1+c^2 x^2}}{5 b^3 c \sqrt {a+b \text {arcsinh}(c x)}}-\frac {8 \text {Subst}\left (\int \frac {e^{-i \left (\frac {i a}{b}-\frac {i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c x)\right )}{15 b^4 c^3}+\frac {8 \text {Subst}\left (\int \frac {e^{i \left (\frac {i a}{b}-\frac {i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c x)\right )}{15 b^4 c^3}+\frac {3 \text {Subst}\left (\int \frac {e^{-i \left (\frac {i a}{b}-\frac {i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c x)\right )}{5 b^4 c^3}-\frac {3 \text {Subst}\left (\int \frac {e^{i \left (\frac {i a}{b}-\frac {i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c x)\right )}{5 b^4 c^3}-\frac {9 \text {Subst}\left (\int \frac {e^{-i \left (\frac {3 i a}{b}-\frac {3 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c x)\right )}{5 b^4 c^3}+\frac {9 \text {Subst}\left (\int \frac {e^{i \left (\frac {3 i a}{b}-\frac {3 i x}{b}\right )}}{\sqrt {x}} \, dx,x,a+b \text {arcsinh}(c x)\right )}{5 b^4 c^3} \\ & = -\frac {2 x^2 \sqrt {1+c^2 x^2}}{5 b c (a+b \text {arcsinh}(c x))^{5/2}}-\frac {8 x}{15 b^2 c^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {4 x^3}{5 b^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {16 \sqrt {1+c^2 x^2}}{15 b^3 c^3 \sqrt {a+b \text {arcsinh}(c x)}}-\frac {24 x^2 \sqrt {1+c^2 x^2}}{5 b^3 c \sqrt {a+b \text {arcsinh}(c x)}}-\frac {16 \text {Subst}\left (\int e^{\frac {a}{b}-\frac {x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c x)}\right )}{15 b^4 c^3}+\frac {16 \text {Subst}\left (\int e^{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c x)}\right )}{15 b^4 c^3}+\frac {6 \text {Subst}\left (\int e^{\frac {a}{b}-\frac {x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c x)}\right )}{5 b^4 c^3}-\frac {6 \text {Subst}\left (\int e^{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c x)}\right )}{5 b^4 c^3}-\frac {18 \text {Subst}\left (\int e^{\frac {3 a}{b}-\frac {3 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c x)}\right )}{5 b^4 c^3}+\frac {18 \text {Subst}\left (\int e^{-\frac {3 a}{b}+\frac {3 x^2}{b}} \, dx,x,\sqrt {a+b \text {arcsinh}(c x)}\right )}{5 b^4 c^3} \\ & = -\frac {2 x^2 \sqrt {1+c^2 x^2}}{5 b c (a+b \text {arcsinh}(c x))^{5/2}}-\frac {8 x}{15 b^2 c^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {4 x^3}{5 b^2 (a+b \text {arcsinh}(c x))^{3/2}}-\frac {16 \sqrt {1+c^2 x^2}}{15 b^3 c^3 \sqrt {a+b \text {arcsinh}(c x)}}-\frac {24 x^2 \sqrt {1+c^2 x^2}}{5 b^3 c \sqrt {a+b \text {arcsinh}(c x)}}+\frac {e^{a/b} \sqrt {\pi } \text {erf}\left (\frac {\sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c^3}-\frac {3 e^{\frac {3 a}{b}} \sqrt {3 \pi } \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{5 b^{7/2} c^3}-\frac {e^{-\frac {a}{b}} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{15 b^{7/2} c^3}+\frac {3 e^{-\frac {3 a}{b}} \sqrt {3 \pi } \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \text {arcsinh}(c x)}}{\sqrt {b}}\right )}{5 b^{7/2} c^3} \\ \end{align*}
Time = 1.18 (sec) , antiderivative size = 417, normalized size of antiderivative = 1.21 \[ \int \frac {x^2}{(a+b \text {arcsinh}(c x))^{7/2}} \, dx=\frac {3 b^2 e^{\text {arcsinh}(c x)}+e^{-\text {arcsinh}(c x)} \left (4 a^2-2 a b+3 b^2+2 (4 a-b) b \text {arcsinh}(c x)+4 b^2 \text {arcsinh}(c x)^2-4 e^{\frac {a}{b}+\text {arcsinh}(c x)} \sqrt {\frac {a}{b}+\text {arcsinh}(c x)} (a+b \text {arcsinh}(c x))^2 \Gamma \left (\frac {1}{2},\frac {a}{b}+\text {arcsinh}(c x)\right )\right )-3 \left (b^2 e^{3 \text {arcsinh}(c x)}+2 e^{-\frac {3 a}{b}} (a+b \text {arcsinh}(c x)) \left (e^{3 \left (\frac {a}{b}+\text {arcsinh}(c x)\right )} (6 a+b+6 b \text {arcsinh}(c x))+6 \sqrt {3} b \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^{3/2} \Gamma \left (\frac {1}{2},-\frac {3 (a+b \text {arcsinh}(c x))}{b}\right )\right )\right )+2 e^{-\frac {a}{b}} (a+b \text {arcsinh}(c x)) \left (e^{\frac {a}{b}+\text {arcsinh}(c x)} (2 a+b+2 b \text {arcsinh}(c x))+2 b \left (-\frac {a+b \text {arcsinh}(c x)}{b}\right )^{3/2} \Gamma \left (\frac {1}{2},-\frac {a+b \text {arcsinh}(c x)}{b}\right )\right )-3 e^{-3 \text {arcsinh}(c x)} \left (b^2+2 (a+b \text {arcsinh}(c x)) \left (6 a-b+6 b \text {arcsinh}(c x)-6 \sqrt {3} e^{3 \left (\frac {a}{b}+\text {arcsinh}(c x)\right )} \sqrt {\frac {a}{b}+\text {arcsinh}(c x)} (a+b \text {arcsinh}(c x)) \Gamma \left (\frac {1}{2},\frac {3 (a+b \text {arcsinh}(c x))}{b}\right )\right )\right )}{60 b^3 c^3 (a+b \text {arcsinh}(c x))^{5/2}} \]
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\[\int \frac {x^{2}}{\left (a +b \,\operatorname {arcsinh}\left (c x \right )\right )^{\frac {7}{2}}}d x\]
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Exception generated. \[ \int \frac {x^2}{(a+b \text {arcsinh}(c x))^{7/2}} \, dx=\text {Exception raised: TypeError} \]
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\[ \int \frac {x^2}{(a+b \text {arcsinh}(c x))^{7/2}} \, dx=\int \frac {x^{2}}{\left (a + b \operatorname {asinh}{\left (c x \right )}\right )^{\frac {7}{2}}}\, dx \]
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\[ \int \frac {x^2}{(a+b \text {arcsinh}(c x))^{7/2}} \, dx=\int { \frac {x^{2}}{{\left (b \operatorname {arsinh}\left (c x\right ) + a\right )}^{\frac {7}{2}}} \,d x } \]
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\[ \int \frac {x^2}{(a+b \text {arcsinh}(c x))^{7/2}} \, dx=\int { \frac {x^{2}}{{\left (b \operatorname {arsinh}\left (c x\right ) + a\right )}^{\frac {7}{2}}} \,d x } \]
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Timed out. \[ \int \frac {x^2}{(a+b \text {arcsinh}(c x))^{7/2}} \, dx=\int \frac {x^2}{{\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )}^{7/2}} \,d x \]
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